jimthompson5910 is such a great help and so important in making a differnce here.

A given line has the equation 2x + 12y = −1.

What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

y = ( ___ )x + 9

find the gradient of the line using the y=mx +c method rearrange 2x+12y=-1 to become 12y=-2x-1...divide both sides by 12 so m=-1/6. To find the slope of a line perpendicular to 2x+12y=-1 when their slopes multiply they give -1. The gradient of the perpendicular line is 6. Using the point it passed through (0,9) use the equation of a line formula which would be y-9/x-0=6

cross multiply and you'll get y=6x+9

jimthompson5910 is such a great help and so important in making a differnce here. A given line has the equation 2x + 12y = −1. What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)? y = ( ___ )x + 9

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jimthompson5910 is such a great help and so important in making a differnce here.

A given line has the equation 2x + 12y = −1.

What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

y = ( ___ )x + 9