The strength of a beam varies inversely with the square of its length. If a 10-foot beam can support 500 pounds how many pounds can a 13 foot beam support? Round the answer to the nearest pound.
![The strength of a beam varies inversely with the square of its length If a 10foot beam can support 500 pounds how many pounds can a 13 foot beam support Round t class=](https://us-static.z-dn.net/files/d8d/1a48fb1cb003adc91c79dc5d2d22e89b.png)
The beam varies inversely with the square of it's length. Let's call S the strength and L the length.
Then we can write:
[tex]S=\frac{k}{L^2}[/tex]For a constant k.
Then, we know that if L = 10ft then S = 500 pounds
We write:
[tex]\begin{gathered} 500=\frac{k}{(10)^2} \\ \end{gathered}[/tex]And solve for k:
[tex]k=500\cdot10^2=500\cdot100=50,000[/tex]Then the inverse relation equation is:
[tex]S=\frac{50,000}{L^2}[/tex]Then, for L = 13ft, the strength is:
[tex]S=\frac{50,000}{13^2}=\frac{50,000}{169}=295.857[/tex]To the nearest pound, a beam of 13ft can support 296 pounds.