The equation of the line is given as,
[tex]8x-5y=14[/tex]The intercepts are the points at which the curve intersects the coordinate axes.
The x-intercept of the line will be the value of 'y' at which the x-coordinate becomes zero. This can be calculated as follows,
[tex]\begin{gathered} 8x-5(0)=14 \\ 8x=14 \\ x=\frac{7}{4} \\ x=1.75 \end{gathered}[/tex]Similarly, the y-intercept is the point at which the line intersects the y-axis. This can be calculated as,
[tex]\begin{gathered} 8(0)-5y=14 \\ -5y=14 \\ y=\frac{-14}{5} \\ y=-2.8 \end{gathered}[/tex]Thus, the x-intercept and y-intercept are obtained as,
[tex]\begin{gathered} \text{ x-intercept}=1.75 \\ \text{ y-intercept}=-2.8 \end{gathered}[/tex]