Question

Consider a series rlc circuit where r = 45.0 ω, c = 15.5 μf, and l = 0.0940 h, driven at a frequency of 50.0 hz. determine the phase angle of the circuit in degrees.

Answer 1

The phase angle of the RLC circuit when the register, inductor, and capacitor are connected in series is 104.35°.

What is an RLC circuit?

The R stands for resistor, L stands for inductor, and C stands for the capacitor.

Consider a series RLC circuit where R = 45.0 ω, C = 15.5 μf, and L  = 0.0940 h, driven at a frequency of 50.0 hz.

Then the ω will be

ω = 2πf  = 314.16 rad/sec.

Then we have

$X _C = \dfrac{1}{\omega C} = \dfrac{1}{314.17*15.5*10^-6} = 205.35$

$X_L = \omega L = 314.17 * 0.0940 = 29.53$

Then the phase change will be

$\phi = tan ^{-1} \dfrac{X_L - X_C}{R}\\\\\phi = tan ^{-1} \dfrac{29.53 - 205.35}{45}\\\\\phi = tan ^{-1} -3.907\\\\\phi = -75.64^o \ \ or \ \ 104.35^o$

More about the RLC circuit link is given below.

https://brainly.com/question/372577