which of the following is not a way to represent the solution of the inequality 2(x+1) >or equal to 20?
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The only incorrect choice in the options is B.
A number line with a closed circle on 9 and shading to the left
Explanations:The given inequality is expressed as:
[tex]2\text{ (x + 1) }\ge\text{ 20}[/tex]Step 1: Open up the brackets[tex]2x\text{ + 2 }\ge\text{ 20}[/tex]Step 2: Collect like terms[tex]\begin{gathered} 2x\text{ }\ge\text{ 20 - 2} \\ 2x\text{ }\ge\text{ 18} \end{gathered}[/tex]Step 3: Divide both sides by 2[tex]\begin{gathered} \frac{2x}{2}\ge\frac{18}{2} \\ x\text{ }\ge\text{ 9} \end{gathered}[/tex]This can also be written as:[tex]9\text{ }\leq\text{ x}[/tex]Drawing this on a number line:This means that x is includes 9 and all the numbers above 9.
From the number line drawn above. A number line with a close circle on 9 and shading to the right is drawn.