Question

suppose that YM has a length 12 in. and its distance from point L is 5in. find the radius of L to the nearest tenth

Answer 1

check the picture below.

Answer 2

Answer:

The radius of circle L is $7.8\ in$  

Step-by-step explanation:

we know that

In the figure the triangle VLM is a right triangle, because VL is pependicular to YM

so

$YV=VM=12/2=6\ in$

LM is the radius of the circle (hypotenuse of triangle VLM)

$VL=5\ in$

Applying the Pythagoras Theorem

$LM^{2}=VM^{2}+VL^{2}$

substitute

$LM^{2}=6^{2}+5^{2}$

$LM^{2}=61$

$LM=7.8\ in$ ------> is the radius