Respuesta :

Original expresion

[tex]\sin (6A)=\cos (9A)[/tex]

Let's use the following relationship to determine the answer

[tex]\sin 6A=\cos (90-6A)[/tex]

Now in the original expression

[tex]\begin{gathered} \cos (90-6A)=\cos 9A \\ 90-6A=9A \\ 90=6A+9A \\ 15A=90 \\ A=\frac{90}{15} \\ A=6 \end{gathered}[/tex]

The answer would be A = 6

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