Question

What is the final concertation of salt in the solution g/L

Answer 1

Answer

61 g/L

Explanation

The first step is to calculate the mass of NaCl in 4.0 g/L solution.

As 1000 ml NaCl solution contains 4 grams of NaCl

So, 200 ml NaCl solution contains:

$\frac{200}{1000}\times4=0.8\text{ grams of NaCl}$

Also, we have to calculate the mass of another NaClin 8% NaCl solution (m/v).

As 100 ml NaCl solution contains 8 grams of NaCl

So, 600 ml NaCl solution contains:

$\frac{600}{100}\times8=48\text{ grams of NaCl}$

Hence, the total mass of NaCl in the final concentration = 0.8 + 48 = 48.8 g

Also, the total volume of NaCl solution = 200 + 600 = 800 mL = 0.8 L

The final step is to calculate the final concentration of salt in the solution using the formula below:

$Concentration\text{ in }g\text{/}L=\frac{Total\text{ }Mass}{Total\text{ Volume in }L}$

So,

$Concentration\text{ in }g\text{/}L=\frac{48.8\text{ g}}{0.8\text{ L}}=61\text{ }g\text{/}L$

Therefore, the final concentration of salt in the solution is 61 g/L