Given,
The gas sample is at STP.
Thus, the temperature of the gas, T=273.15 K
The pressure of the gas, P=10⁵ Pa
The quantity of the gas, n=2.3 mol
The value of the gas constant is R=8.314 m³·Pa·K⁻¹·mol⁻¹
From the ideal gas equation,
[tex]\begin{gathered} PV=\text{nRT} \\ V=\frac{\text{nRT}}{P} \end{gathered}[/tex]Where V is the volume of the gas.
On substituting the known values,
[tex]\begin{gathered} V=\frac{2.3\times8.314\times273.15}{10^5} \\ =0.052m^3 \end{gathered}[/tex]Thus the volume of the given gas at STP is 0.052 m³
