Given:
The two similar polygons are given, whose sides are proportional.
[tex]\frac{E^{\prime}D^{\prime}}{ED}=\frac{A^{\prime}E^{\prime}}{AE}=\frac{A^{\prime}B^{\prime}}{AB}=\frac{B^{\prime}C^{\prime}}{BC}=\frac{C^{\prime}D^{\prime}}{CD}[/tex]
To find the value of x.
consider,
[tex]\begin{gathered} \frac{E^{\prime}D^{\prime}}{ED}=\frac{A^{\prime}E^{\prime}}{AE} \\ \frac{6}{9}=\frac{x}{10} \\ x=\frac{6\times10}{9} \\ x=\frac{20}{3} \\ x=6\frac{2}{3} \end{gathered}[/tex]
Answer: option c)
