re The point-slope form of a line is
[tex]y-y_1=m(x-x_1)[/tex]The slope m of the line passing through these two points is the difference between their y coordinates divided by the difference between their x - coordinate.
[tex]m=\frac{6-4}{4-3}[/tex][tex]m=2[/tex]Now we need only find the y-intercept.
Let us use the point (3, 4) which tells us that at x = 3, y = 4; therefore,
[tex]4-y_1=2(3)[/tex][tex]y_1=-2[/tex]Hence, the question of our line in point-slope form is
[tex]\textcolor{#FF7968}{y+2=2x}[/tex]Alternatively, when we have the slope of the line we would just use one of the points to quickly write the point-intercept form.
The y_1 and x_1 in the very first equation are the coordinates of one of the points on the line =. We know that one of the point on our line is (3, 4);