Respuesta :

[tex]n^{-x}=\frac1{n^x}[/tex]

[tex]\textcircled1\ \frac1{49}=\frac1{7^2}=\boxed{7^{-2}}[/tex]

[tex]\textcircled2\ \frac{27}{125}=\frac{3^3}{5^3}=(\frac35)^3=\frac1{(\frac{5}{3})^3}=\boxed{\left(\frac53\right)^{-3}}[/tex]


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