We are given the following rational equation
[tex]\frac{3}{x}-\frac{1}{3}=\frac{1}{6}[/tex]
As you can see, the value of x cannot be equal to 0 because it will make the fraction undefined.
Now, let us solve the equation
[tex]\begin{gathered} \frac{3}{x}-\frac{1}{3}=\frac{1}{6} \\ \frac{3}{x}=\frac{1}{6}+\frac{1}{3} \\ \frac{3}{x}=\frac{1+2(1)}{6} \\ \frac{3}{x}=\frac{1+2}{6} \\ \frac{3}{x}=\frac{3}{6} \\ \frac{3}{x}=\frac{1}{2} \\ 3\cdot2=x\cdot1 \\ 6=x \\ x=6 \end{gathered}[/tex]
Therefore, the value of x is 6
The value for x cannot be equal to 0