Answer:
x = 43
Step-by-step explanation:
125^(3x+7)=25^(5x−11)
Rewriting the bases as powers of 5
125 = 5^3 and 25 = 5^2
5^3 ^ (3x+7) = 5^2^(5x-11)
We know a^b^c = a^ (b*c)
5^(3 * (3x+7)) = 5^(2*(5x-11))
Distribute
5^(9x+21) = 5^(10x-22)
The bases are the same so the exponents are the same
9x+21 = 10x-22
Subtract 9x from each side
9x+21 -9x = 10x-9x-22
21 = x-22
Add 22 to each side
21+22 = x-22+22
43 = x
