Solve the right triangle with b=1.97 and c= 4.16. Round off the results according to the table below


Hello!
To solve this exercise, we must use the Pythagoras Theorem:
So, we will have:
[tex]\begin{gathered} c^2=a^2+b^2 \\ \end{gathered}[/tex]Knowing it, let's replace it with the variables:
• b ,= 1.97
,• c ,= 4.16
[tex]\begin{gathered} 4.16^2=a^2+1.97^2 \\ 17.3056=a^2+3.8809 \\ 17.3056-3.8809=a^2 \\ a^2=13.4247 \\ a=\sqrt{13.4247} \\ a\cong3.66 \end{gathered}[/tex]The measurement of the third side of the right triangle is approximately 3.66.