Respuesta :

Solution

[tex]x^2-10x+y^2+6y-30=0[/tex]

Now, the circle equation

[tex]\left(x−a\right)^2+\left(y−b\right)^2=r^2\:\:\mathrm{is\:the\:circle\:equation\:with\:a\:radius\:r,\:centered\:at}\:\left(a,\:b\right)[/tex][tex]undefined[/tex]

Rewrite in standard form

[tex]\left(x-5\right)^2+\left(y-\left(-3\right)\right)^2=8^2[/tex]

Therefore the circle properties

[tex]\left(a,\:b\right)=\left(5,\:-3\right),\:r=8[/tex]

The final answer

[tex]\mathrm{Circle\:with\:center\:at}\:\left(5,\:-3\right)\:\mathrm{and\:radius}\:r=8[/tex]

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