Respuesta :

EXPLANATION

Since we have the expression:

[tex]\frac{7x+42}{x^2+13x+42}[/tex]

Factoring 7x + 42:

[tex]\mathrm{Rewrite\:}42\mathrm{\:as\:}7\cdot \:6[/tex][tex]=7x+7\cdot \:6[/tex]

Factor out common term 7:

[tex]=7\left(x+6\right)[/tex][tex]=\frac{7\left(x+6\right)}{x^2+13x+42}[/tex]

Factor x^2+13x+42:

Breaking the expression into groups:

[tex]=\left(x^2+6x\right)+\left(7x+42\right)[/tex]

Factor out x from x^2+6x:

[tex]=x\left(x+6\right)[/tex]

Factor out 7 from 7x + 42:

[tex]=x\left(x+6\right)+7\left(x+6\right)[/tex]

Factor out common term x+6:

[tex]=\frac{7\left(x+6\right)}{\left(x+6\right)\left(x+7\right)}[/tex][tex]\mathrm{Cancel\:the\:common\:factor:}\:x+6[/tex]

The final expression is as follows:

[tex]=\frac{7}{x+7}[/tex]

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