Given:
The number of vibrations of the tuning fork is,
[tex]51\text{8 times}[/tex]in,
[tex]t=3.50\text{ s}[/tex]To find:
The frequency of the fork
Explanation:
The frequency is the number of vibrations in 1 second
The frequency for the given fork is,
[tex]\begin{gathered} \frac{The\text{ total vibrations}}{The\text{ time}} \\ =\frac{518}{3.50} \\ =148\text{ Hz} \end{gathered}[/tex]Hence, the frequency is 148 Hz.