Respuesta :

Given:

The number of vibrations of the tuning fork is,

[tex]51\text{8 times}[/tex]

in,

[tex]t=3.50\text{ s}[/tex]

To find:

The frequency of the fork

Explanation:

The frequency is the number of vibrations in 1 second

The frequency for the given fork is,

[tex]\begin{gathered} \frac{The\text{ total vibrations}}{The\text{ time}} \\ =\frac{518}{3.50} \\ =148\text{ Hz} \end{gathered}[/tex]

Hence, the frequency is 148 Hz.

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