I don't understand how to do this question. the equation is [tex]g(x) = \pi \sin( \frac{x}{2} ) + \pi[/tex]

We have the next function
[tex]g(x)=\pi\sin (\frac{x}{2})+\pi[/tex]the amplitude is π
The natural frequency is
[tex]\omega=\frac{1}{2}[/tex]with this, we can calculate the frequency and the period
[tex]\omega=2\pi f=\frac{2\pi}{T}[/tex]for frequency
[tex]f=\frac{\omega}{2\pi}=\frac{\frac{1}{2}}{2\pi}=\frac{1}{4\pi}[/tex]the period is
[tex]T=\frac{1}{f}=4\pi[/tex]The phase shift is 0
the vertical translation is π
the equation of midline is
[tex]y=\pi[/tex]The graph of the function is
where g(x) is the graph in red and the midline is the graph in blue