Question

A 2,113kg truck drives along a circular round-a-bout with a radius of 49 m at a constant speed of 12 m/s. The centripetal acceleration is--------m/s/sa=v^2/r

Answer 1

• Given:

,

• Mass = 2113 kg

,

• Radius, r = 49 m

,

• Speed, v = 12 m/s

Let's find the centripetal acceleration.

To find the centripetal acceleration, apply the formula:

$a=\frac{v^2}{r}$

Where:

a is the centripetal acceleration

v is the speed

r is the radius

Thus, we have:

$\begin{gathered} a=\frac{12^2}{49} \\ \\ a=\frac{144}{49} \\ \\ a=2.94\text{ m/s} \end{gathered}$

Therefore, the centripetal acceleration is 2.94 m/s²

• ANSWER:

2.94 m/s²