Solution:
Given the expression:
[tex]\frac{6x^2-7x-5}{3-x}[/tex]
To simplify, we can rexpress the above expression as
[tex]\frac{6x^2-7x-5}{-x+3}[/tex]
Thus, simplifying using long division, we have
Hence, we have
[tex]\frac{6x^2-7x-5}{3-x}=-6x-11+\frac{28}{3-x}[/tex]
