The coordinates of quadrilateral FGHJ are F(-5,-3) G(-3,3) H(3,5) and J(7,-1). Find the midpoint of HJAnswers: A.(1,-2)B.(5,2)C.(0,4)D.(-4,0)

Respuesta :

Answer:

B. (5, 2)

Explanation:

The coordinates of a midpoint of a segment that goes from (x1, y1) yo (x2, y2) are

[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

So, the midpoint of HJ can be founded replacing (x1, y1) by H(3, 5) and (x2, y2) by J(7, -1)

[tex](\frac{3+7}{2},\frac{5+(-1)}{2})=(\frac{10}{2},\frac{4}{2})_{}=(5,2)_{}[/tex]

Therefore, the answer is

B. (5, 2)

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