Question

M is the midpoint of segment AB. Q is the midpoint of segment MB. A is 2 located at (-3,5), and B is located at (9.-9). What are the coordinates of Q?

Answer 1

M is the mid point of line segment AB.

Q is the mid point of line segment AB.

Coordinates of A is (-3,5)

Coordinates of B is (9,-9)

The expression for mid point in the coordinate geometry is expressed as :

$(\frac{x_1+x_2}{2},\text{ }\frac{y_1+y_2}{2})\text{ = Mid Point (x, y)}$

Substitute the value and solve

$\begin{gathered} \text{From the given coordinates of A (-3,5) and B(-9,9)} \\ x_1=-3,x_2=-9,y_1=5,y_2=9 \\ \text{Mid Point Q(x,y)=(}\frac{-3+(-9)}{2},\frac{5+9}{2}) \\ \text{Mid Point Q(x,y)=(}\frac{-3-9}{2},\frac{5+9}{2}) \\ \text{Mid Point Q(x,y)=(}\frac{-12}{2},\frac{14}{2}) \\ \text{Mid Point Q(x,y)=(}-6,7) \end{gathered}$

So, teh coordinates of Q is (-6, 7)

Answer : Q = (-6,7)