Question

can someone show me how to solve this? the lesson didnt show me how to do it.$\frac{x^{2} }{2} -32 = 0$

Answer 1

Answer:

x=-8,8

Step-by-step explanation:

$\frac{x^2}{2} -32=0\\multiply ~by~2\\x^2-64=0\\x^2-8^2=0\\(x+8)(x-8)=0\\ether~ x=-8\\or~x-8=0\\x=8\\x=-8,8x=-8$

missing  either x+8=0

x=-8