Question

Part B: Now perform the calculations you set up in part A Round your answer to the nearest whole number It will take _ seconds for the device to release 154 grams of the gas

Answer 1

Step 01: To write the relation, begin using the relation for seconds.

$\frac{1s}{0.25L}$

Step 02: To eliminate L, use the other relation, putting the liters in the numerator:

$\frac{1L}{4.3g}\cdot\frac{1s}{0.25L}$

Step 03: Multiply everything by 154g.

$154g\cdot\frac{1L}{4.3g}\cdot\frac{1s}{0.25L}$

Step 04: Multiply the numerators and the denominators.

$\frac{154g\cdot1L\cdot1s}{1\cdot4.3g\cdot0.25L}$

Step 05: Multiply the numbers and simplify the units that are in the numerator and in the denominator.

$\begin{gathered} \frac{154\cdot1\cdot1g\cdot L\cdot s}{1\cdot4.3\cdot0.25\cdot g\cdot L} \\ \frac{154s}{1.075} \\ =143.3s \end{gathered}$

Answer: It will take 143.3 seconds.