Question

Hello pls do it and I will compare mine to your thanks person I don’t know

Answer 1

The given figure is compounded by a semicircle and a triangle as can be seen in the following diagram:

The area of a semicircle is given by the formula:

$A_{sc}=\frac{\pi r^2}{2}$

Where r is the radius of the semicircle, which is the half of the given diameter, then r=16/2=8 m. By replacing this value we can find the area of the first part:

$A_{sc}=\frac{\pi(8m)^2}{2}=\frac{\pi\cdot64m^2}{2}=100.5m^2$

Now, the area of the triangle is given by the formula:

$A_t=\frac{b\cdot h}{2}$

Where b is the base and h is the height. The base is b=16 m and h=12 m. Replace these values and find the area of this part:

$A_t=\frac{16m\cdot12m}{2}=\frac{192m^2}{2}=96m^2$

Finally, the total area of the figure is the addition of the two areas we found:

$A_{\text{fig}}=100.5m^2+96m^2=196.5m^2$

The answer is B. 196.5 m^2