Answer:
17%
Explanation:
The number of gold hoop earrings = 2
The number of silver hoop earrings = 2
Total number of earrings = 2+2 =4
If two earrings are selected at random:
[tex]\begin{gathered} \text{P}(\text{ the first is a silver hoop earring\rparen}=\frac{2}{4} \\ P(\text{the second is a silver hoop earring\rparen}=\frac{1}{3} \end{gathered}[/tex]Therefore,multiply the two probabilities:
[tex]\begin{gathered} =\frac{2}{4}\times\frac{1}{3} \\ =\frac{2}{12} \\ =\frac{1}{6} \\ =0.1667 \\ =16.67\% \\ \approx17\% \end{gathered}[/tex]The probability that both are silver hoop earrings is 17% (rounded to the nearest whole percent).
