Answer:
Explanation:
Given:
[tex]f(x)=3x^2+6x-2[/tex]
There are ways to find the minimum value of the given function. We graph it or express it into vertex form:
For the graph:
Based on the graph, the lowest point is at (-1,-5).
We can double check this by expressing it into vertex form:
[tex]\begin{gathered} 3x^2+6x-2\text{ = }3(x+1)^2-5 \\ \text{where:} \\ h=-1 \\ k=-5 \\ or \\ (-1,-5) \end{gathered}[/tex]
Therefore, the minimum value is (-1,-5)
