Geo1574
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Given H (6,7) and I (-7,6), if point G lies 1/2 of along the way HI, Santiago Argues That Point G Is Located At The Origin. Is Santiago Correct? Justify Your Answer.

Respuesta :

if G is halfway, then it is the midpoint..
midpoint formula : (x1 + x2)/2 , (y1 + y2)/2
(6,7)....x1 = 6 and y1 = 7
(-7,-6)....x2 = -7 and y2 = -6
now we sub
m = (6 - 7) / 2 , (7 - 6)/2
m = (-1/2 , 1/2)

Santiago is wrong. Point G lies at (-1/2,1/2)


Santiago was incorrect, as the point [tex]G[/tex] is located at [tex](-\frac{1}{2}, \frac{1}{2})[/tex]

Explanation

The co ordinates of the given points are:   [tex]H(6,7)[/tex] and [tex]I(-7,-6)[/tex]

If point [tex]G[/tex] lies [tex]\frac{1}{2}[/tex] of along the way [tex]\overline{HI}[/tex], that means [tex]G[/tex] should be the midpoint of line [tex]\overline{HI}[/tex].

Mid-point formula is:  [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex] , where [tex](x_{1}, y_{1})[/tex] and [tex](x_{2}, y_{2})[/tex] are two endpoints.

So, the co ordinate of the midpoint of [tex]H[/tex] and [tex]I[/tex] will be......

[tex](\frac{6+(-7)}{2},\frac{7+(-6)}{2})\\ \\ =(-\frac{1}{2}, \frac{1}{2})[/tex]

Co ordinate of the origin is always [tex](0,0)[/tex]

So, Santiago was incorrect, as the point [tex]G[/tex] is located at [tex](-\frac{1}{2}, \frac{1}{2})[/tex]

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