Respuesta :
if G is halfway, then it is the midpoint..
midpoint formula : (x1 + x2)/2 , (y1 + y2)/2
(6,7)....x1 = 6 and y1 = 7
(-7,-6)....x2 = -7 and y2 = -6
now we sub
m = (6 - 7) / 2 , (7 - 6)/2
m = (-1/2 , 1/2)
Santiago is wrong. Point G lies at (-1/2,1/2)
midpoint formula : (x1 + x2)/2 , (y1 + y2)/2
(6,7)....x1 = 6 and y1 = 7
(-7,-6)....x2 = -7 and y2 = -6
now we sub
m = (6 - 7) / 2 , (7 - 6)/2
m = (-1/2 , 1/2)
Santiago is wrong. Point G lies at (-1/2,1/2)
Santiago was incorrect, as the point [tex]G[/tex] is located at [tex](-\frac{1}{2}, \frac{1}{2})[/tex]
Explanation
The co ordinates of the given points are: [tex]H(6,7)[/tex] and [tex]I(-7,-6)[/tex]
If point [tex]G[/tex] lies [tex]\frac{1}{2}[/tex] of along the way [tex]\overline{HI}[/tex], that means [tex]G[/tex] should be the midpoint of line [tex]\overline{HI}[/tex].
Mid-point formula is: [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex] , where [tex](x_{1}, y_{1})[/tex] and [tex](x_{2}, y_{2})[/tex] are two endpoints.
So, the co ordinate of the midpoint of [tex]H[/tex] and [tex]I[/tex] will be......
[tex](\frac{6+(-7)}{2},\frac{7+(-6)}{2})\\ \\ =(-\frac{1}{2}, \frac{1}{2})[/tex]
Co ordinate of the origin is always [tex](0,0)[/tex]
So, Santiago was incorrect, as the point [tex]G[/tex] is located at [tex](-\frac{1}{2}, \frac{1}{2})[/tex]