For a geometric sequence:
[tex]10,-40,160[/tex]Given data:
The first term of the sequence is 10
The second term of the sequence is -40
The third term of the sequence is 160
The general formula for a geometric sequence is
[tex]T_n=ar^{n-1}[/tex]To get the 11th term, n=11
The common ratio is
[tex]\frac{T_2}{T_1}=\frac{-40}{10}=-4[/tex]The parameters we
