can someone please give me the answers to these 2 will add 40 points

Answer:
Step-by-step explanation:
Use sine and cosine.
[tex]sine=\dfrac{opposite}{hypotenuse}[/tex]
[tex]cosine=\dfrac{adjacent}{hypotenuse}[/tex]
Q8.
We have:
[tex]opposite=y\\\\adjacent=x\\\\hypotenuse=18\\\\\alpha=18^o\\\\\sin18^o\approx0.309\\\\\cos18^o\approx0.9511[/tex]
Substitute:
[tex]\dfrac{y}{18}=0.309[/tex] multiply both sides by 18
[tex]y=5.562\to y\approx5.6[/tex]
[tex]\dfrac{x}{0.9511}=18[/tex] multiply both sides by 0.9511
[tex]x=17.1198\to x\approx17.1[/tex]
Q9.
We have:
[tex]opposite=y\\\\adjacent=x\\\\hypotenuse=26\\\\\alpha=68^o\\\\\sin68^o\approx0.9272\\\\\cos68^o\approx0.3746[/tex]
Substitute:
[tex]\dfrac{y}{26}=0.9272[/tex] multiply both sides by 26
[tex]y=24.1072\to y\approx24.1[/tex]
[tex]\dfrac{x}{26}=0.3746[/tex] multiply both sides by 26
[tex]x=9.7396\to x\approx9.7[/tex]