Question

the area of a semicircle with a diameter of 12.8in.. Round to the nearest tenth

Answer 1

Answer:

64.3 in²

Explanation:

The area of a semicircle can be calculated as:

$A=\frac{\pi\times r^2}{2}$

Where π is approximately 3.14 and r is the radius of the circle.

The radius of the circle is half of the diameter, so the radius of a circle with a diameter of 12.8in is:

$\text{radius = }\frac{Diameter}{2}=\frac{12.8\text{ in}}{2}=6.4\text{ in}$

Now, we can replace r by 6.4 in on the equation of the Area and get:

$\begin{gathered} A=\frac{3.14\times(6.4in)^2}{2} \\ A=\frac{3.14\times40.96in^2}{2} \\ A=\frac{128.61in^2}{2} \\ A=64.3in^2 \end{gathered}$

Therefore, the answer is 64.3 in².