Homework:Chapter 08.4Question 5, 8.4.C-3HW Score: 18%, 4.5 of 25 pointsPoints: 0.5 of 1Question content area topPart 1Find the area of the shaded portion of the figure

In the given figure the diameter of the larger circle is 2.5 inches
and the diameter of the smaller circle is 0.8 inches.
The radius is given as, r = d/2 where d is the diameter.
Then,
the radius of the larger circle = R = 2.5/2 inches = 1.25 inches
and the radius of the smaller circle is = r = 0.8/2 inches = 0.4 inches
Now the area of the circle is given as
[tex]\begin{gathered} A=\pi r^2 \\ where\text{ r is the radius of the circle} \end{gathered}[/tex]So the area of the shaded portion will be
[tex]\begin{gathered} Required\text{ area=}\pi R^2-\pi r^2 \\ Required\text{ area = }\pi[R^2-r^2]=\frac{22}{7}\times[1.25^2-0.4^2] \\ Required\text{ area =3.14}\times1.4025\text{ sq inches} \\ Required\text{ area = 4.40385 sq inches} \end{gathered}[/tex]Hence the area of the shaded portion will be 4.40385 sq inches.