Respuesta :

Okay, here we have this:

Considering the provided information, we obtain the following:

C=90°

A=180°-C-B

A=180°-90°-70°

A=20°

[tex]\begin{gathered} \tan (B)=\frac{b}{a} \\ \tan (70)=\frac{b}{32} \\ b=32\cdot\tan (70) \\ b\approx87.92 \\ c=\sqrt[]{32^2+87.92^2} \\ c\approx93.56 \end{gathered}[/tex]

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