We have the following:
The formula that represents this situation is the following
[tex]A=P\cdot(1-r)^x[/tex]Where r is the depreciation rate, if we equate this part of education with the given of the statement we are left
[tex]\begin{gathered} 1-r=0.86 \\ \text{solving r} \\ r=1-0.86 \\ r=0.14 \end{gathered}[/tex]Therefore the depreciation rate is 0.14 or 14%