SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the quadratic equation
[tex]3u^2+7u-3=0[/tex]STEP 2: Write the needed terms
[tex]\begin{gathered} By\text{ comparison with standard quadratic equation of the form:} \\ ax^2+bx+c=0 \\ a=3,b=7,c=-3 \end{gathered}[/tex]STEP 3: Write the quadratic formula
[tex]u_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]STEP 4: Substitute the values into the formula
[tex]u_{1,2}=\frac{-7\pm\sqrt{7^2-4\cdot3\cdot(-3)}}{2\cdot3}[/tex]STEP 5: Simplify:
[tex]u_{1,2}=\frac{-7\pm\sqrt{49+36}}{6}=\frac{-7\pm\sqrt{85}}{6}[/tex]STEP 6: Separate the solutions
[tex]u_1=\frac{-7+\sqrt{85}}{6},u_2=\frac{-7-\sqrt{85}}{6}[/tex]STEP 7: Simplify:
[tex]\begin{gathered} u_1=0.369924076\approx0.37 \\ u_2=-2.70325741\approx-2.70 \end{gathered}[/tex]Hence, the values of u are:
[tex]\begin{gathered} 0.37 \\ -2.70 \end{gathered}[/tex]