Question

Calculate the applied force to the piston with a 12cm radius required to elevate a weight of 2.0X104N by the piston with a 36cm radius in a hydraulic lift.

2.9 × 103 N

5.0 × 103 N

6.7 × 103 N

2.2 × 103 N

Answer 1

Answer:

Option D is the correct answer.

Explanation:

Refer the figure given.

By Pascal's principle we have

            $\frac{F_1}{A_1}=\frac{F_2}{A_2}$

F2 = 2 x 10⁴ N

$A_1=\frac{\pi\times (12\times 10^{-3})^2}{4}=1.13\times 10^{-4}m^2\\\\A_2=\frac{\pi\times (36\times 10^{-3})^2}{4}=1.02\times 10^{-3}m^2$

Substituting

      $\frac{F_1}{1.13\times 10^{-4}}=\frac{2\times 10^4}{1.02\times 10^{-3}}\\\\F_1=2.22\times 10^3N$

Option D is the correct answer.