We wioll have the following:
First, we determine the minimum distance traveled.
This velocity is given by the tortoise.
We know that the hare stops for 3 minutes, now we determine the distance that the tortoise traverses in this time:
[tex]d=(0.14m/s)(3min\ast60s/min)\Rightarrow d=25.2m[/tex]And we know that the tortoise won by 25 cm, so the minimum distance traversed will be:
[tex]d_{min}=25.2m+0.25m\Rightarrow d_{min}=25.45m[/tex]So, the minimum distance traversed by both the torotise and the hare is 25.45 m.
a)
Now, we determine the minimum time it took [Using the tortoise's speed], that is:
[tex]\begin{gathered} t=\frac{(25.45m)(1s)}{0.14m}\Rightarrow t=\frac{2545}{14}s \\ \\ \Rightarrow t=181.7857143...s\Rightarrow t\approx181.79s \end{gathered}[/tex]So, it took as a minimum 181.79 s.
b)
The lenght of the total race as a minimum we determined was 25.45 m.