Question

(this is a rhombus btw) for what value of x is the figure the given special parallelogram? HELP PLS, show work.

Answer 1

Answer:

x = 2 or 3

Step-by-step explanation:

Diagonal of a rhombus bisects the vertex angles. So,

$x^{2} =5x-6$

$=> x^{2} -5x + 6 = 0$

Lets factorise the eqn.

$=> x^{2} - 2x - 3x + 6 = 0$

$=> x (x - 2) -3(x-2)$

$=> (x-2)(x-3) = 0$

Here x will have 2 values.

1) $x-2=0$

$=> x =2$

2) $x - 3 = 0$

$=> x = 3$