The Solution.
The frequency table of the given data is as below:
The data in the table above is QUANTITATIVE.
The relative frequency of the data above is calculated thus:
The relative frequency of Astronomy (A) is
[tex]\frac{n\text{umber of A}}{\text{total frequency}}=\frac{6}{20}=\frac{3}{10}=0.3[/tex]The relative frequency of Biology (B) is
[tex]\frac{n\text{umber of B}}{\text{total frequency}}=\frac{2}{20}=\frac{1}{10}=0.1[/tex]The relative frequency of Chemistry (C) is
[tex]\frac{n\text{umber of C}}{\text{total frequency}}=\frac{4}{20}=\frac{1}{5}=0.2[/tex]The relative frequency of Mathematics (M) is
[tex]\frac{n\text{umber of M}}{\text{total frequency}}=\frac{3}{20}=0.15[/tex]The relative frequency of English is
[tex]\frac{n\text{umber of M}}{\text{total frequency}}=\frac{5}{20}=\frac{1}{4}=0.25[/tex]