AB is tangent to the circle at B. m

Angle Formed by Tangent and Secant = 1/2 (DIFFERENCE of Intercepted Arcs)
< A = 1/2 ( arc BC - arc BD)
27 = 1/2 ( 114 - x)
Multiply each side by 2
27*2 = 2* 1/2 ( 114 - x)
54 = ( 114 - x)
Subtract 114 from each side
54 -114 = 114-x-114
-60 = -x
Multiply by -1
60 = x
Next find arc CD
The total circle arc is 360
BC + CD + DB = 360
114 + CD + 60 = 360
CD = 360 - 114 - 60
CD =186
Angle y = 1/2 arc CD
y = 1/2 ( 186)
y =93