SofiyahE699805
SofiyahE699805
29-10-2022
Mathematics
contestada
solve for b3/4b + 9 = 21
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AdeliahP758154
AdeliahP758154
29-10-2022
[tex]\frac{3}{4b}+9=21[/tex]
subtract 9 from both-side
[tex]\frac{3}{4b}=21-9[/tex][tex]\frac{3}{4b}=12[/tex]
cross multiply
[tex]48b=3[/tex]
Divide both-side by 48
[tex]b=\frac{3}{48}[/tex][tex]b=\frac{1}{16}[/tex]
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