I need help with this practice problem from my trig prep book

Given:
[tex]r=3-3\sin (\theta)[/tex]To find:
We need to find the type of the graph of the given polar equation.
Explanation:
The given equation is of the form
[tex]r=a-b\sin (\theta)[/tex]where a=3 and b=-3.
This equation is the general equation of the limacon.
Hence the given equatLimaconLimaconlimacon.
The graph of the equation:
Final answer:
The type of polar curve is Limacon.