Answer:
the focus of the parabola is:[tex](1,\frac{-15}{4} )[/tex]
Step-by-step explanation:
we will convert this given equation of the parabola into the general parabola equation of the type [tex]4a(y-k)=(x-h)^2[/tex]
on converting the given equation of the type [tex]y=x^2-2 x-3[/tex] into general equation of parabola we get that [tex]4×\frac{1}{4} (y-(-4))=(x-1)^2[/tex]
clearly here vertex=(h,k)=(1,-4) and [tex]a=\frac{1}{4}[/tex]
so focus=(h,k+a)
hence the given parabola has focus:[tex](1,\frac{-15}{4})[/tex]