Using the formula area equals 1/2 times base times height write an expression for the triangle ABC

The first thing I have to see is that we have 3 triangles, two of them have the same height C. We have to find the area of those 2 and subtracting it will give us the area of ABC
[tex]\begin{gathered} A1=\frac{xh}{2} \\ A2=\frac{(x+c)h}{2} \\ A_{abc}=A2-A1 \\ \\ \end{gathered}[/tex][tex]\begin{gathered} A_{abc}=\frac{(x+c)h}{2}-\frac{xh}{2} \\ A_{abc}=\frac{1}{2}(xh+ch-xh) \\ A_{abc}=\frac{1}{2}(ch) \\ A_{abc}=\frac{c\cdot h}{2} \end{gathered}[/tex]