Respuesta :

The given equation is

[tex]\frac{1}{3}x=\frac{1}{3}+\frac{6}{x}[/tex]

First, we subtract 6/x on each side

[tex]\frac{1}{3}x-\frac{6}{x}=\frac{1}{3}+\frac{6}{x}-\frac{6}{x}\rightarrow\frac{1}{3}x-\frac{6}{x}=\frac{1}{3}[/tex]

Second, we solve the difference in the left side of the equation

[tex]\frac{x^2-18}{3x}=\frac{1}{3}[/tex]

Third, we simplify numbers 3, and multiply the equation by x

[tex]\frac{x(x^2-18)}{x}=x\rightarrow x^2-18=x[/tex]

Fourth, we subtract x on each side to get the quadratic equation

[tex]x^2-18-x=x-x\rightarrow x^2-18-x=0[/tex]

Additionally, we need to find two number which product is 18, and which difference is 1. Those numbers are no integers, so, we must use a calculator.

Using a calculator, the solutions are

[tex]x_1=4.77,x_2=-3.77[/tex]

RELAXING NOICE
Relax