Given:
The length of the parallel sides,
a=17.4 m
b=44.1 m
The height, h=23.5 m
The measurements of the other two sides are,
c=27.5m and d=26.6m.
To find the area of the trapezium:
Using the formula,
[tex]\begin{gathered} A=\frac{1}{2}\times(a+b)\times h_{} \\ =\frac{1}{2}\times(17.4+44.1)\times23.5 \\ =\frac{1}{2}\times61.5\times23.5 \\ =722.625\text{ square meters} \end{gathered}[/tex]
Hence, the area of the figure is 722.6 sq. m (rounded to the nearest tenth).
To find the perimeter of the trapezium:
[tex]\begin{gathered} P=a+b+c+d \\ =17.4+44.1+27.5+26.6 \\ =115.6\text{ m} \end{gathered}[/tex]
Hence, the perimeter of the figure is 115.6 m.
