Question

HELP
What is the equation in point-slope form of a line that passes through the points (7, -8) and (-4, 6)

A: y-6= -14/11(x+4)
B: y+6= -2/3(x-4)
C: y-6= -2/3(x+4)
D: y+6= -14/11(x-4)

Answer 1

Answer:

A

Step-by-step explanation:

The point slope form of the equation is $y-y_1 = m( x-x_1)$ where m is the slope and $(x_1,y_1)$  is a point on the line.

First find the slope by subtracting two points from the line.

$\frac{y_2-y_1}{x_2-x_1} = \frac{6--8}{-4-7} =\frac{14}{-11} =-\frac{14}{11}$

To write the equation substitute in:

$y-6 = -\frac{14}{11} (x--4)\\\\y-6 = -\frac{14}{11} (x+4)$

The answer is A.