The correct answer is options A and E.
f(x) = 6x + 4
f(1) = 6(1) + 4 = 10
f(2) = 6(2) + 4 = 16
f(3) = 6(3) + 4 = 22
[tex]\begin{gathered} \text{When n=1,} \\ a_1=10 \\ a_{n+1}=a_{1+1}=a_2=a_1+6\text{ = 10+6=16} \\ _{}when\text{ n=2} \\ a_{n+1}=a_{2+1}=a_3=a_2+6=16+6=22 \end{gathered}[/tex]Clearly, options A and E are the same sequences.
