ok
Formula
[tex]\text{ A = }\frac{\thetaR^2}{2}[/tex]
Solve for R
[tex]\text{ R = }\sqrt[]{\frac{2A}{\theta}}[/tex]
Substitution
[tex]\text{ R = }\sqrt[]{\frac{2(3\pi)}{\frac{2\pi}{3}}}[/tex][tex]\text{ R = }\sqrt[]{\frac{6\pi}{\frac{2\pi}{3}}}[/tex]
[tex]\text{ R = }\sqrt[]{\frac{18\pi}{2\pi}}[/tex][tex]\text{ R = }\sqrt[]{9}[/tex]
R = 3
The answer is 3, I'm looking for my mistake.
